8x^2+2x-85=0

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Solution for 8x^2+2x-85=0 equation:



8x^2+2x-85=0
a = 8; b = 2; c = -85;
Δ = b2-4ac
Δ = 22-4·8·(-85)
Δ = 2724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2724}=\sqrt{4*681}=\sqrt{4}*\sqrt{681}=2\sqrt{681}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{681}}{2*8}=\frac{-2-2\sqrt{681}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{681}}{2*8}=\frac{-2+2\sqrt{681}}{16} $

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